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The second line of Lyman series of H coincides with the sixth line of Paschen series of an ionic species X. For example the Lyman series (nf = 1 in Balmer-Rydberg equation) occurs in the ultraviolet region while the Balmer (nf = 2) series occurs in the . Example \(\PageIndex{1}\): The Lyman Series. Calculate the ratio of ionization energies of H and D. Chemistry. the shortest line of Lyman series p = 1 and n = ∞ Balmer Series: If the transition of electron takes place from any higher orbit (principal quantum number = 3, 4, 5, …) to the second orbit (principal quantum number = 2). The wavelength of the first line of Lyman series for hydrogen atom is equal to that of the second line of Balmer series tor a hydrogen like ion. The second line of Lyman series of H coincides with the 6 t h line of Paschen series of an ionic species X. The photon radiated from hydrogen corresponding to 2nd line of Lyman series is absorbed by a hydrogen like atom 'X' in 2nd excited state. If \$\upsilon_{1}\$ is the frequency of the series limit of Lyman series, \$\upsilon_{2}\$ is the frequency of the first line of Lyman series and \$\upsilon_{3}\$ is the frequency of the series limit of the Balmer series… As you notice and the values are decreasing in the series due to the derivation and their state which is Ultra Violet. To what energy level will the hydrogen atom be excited? Calculate the wavelength of the second Lyman series and the second line of the Balmer series. In what region of the electromagnetic spectrum does this series lie ? The line spectrum of the Lyman series is formed from transitions of electrons to or from the lowest energy …